I would appreciate any comments or pointers.
CFP3 gave me a popup firewall alert.
It said PopPeeper.exe is trying to receive a connection from the Internet
Remote: 222.180.34.2 - TCP
Port: 1080
That computer, 222.180.34.2, is in china.
I had an email just before the alert.
It had a webbug (here is an edited version):
app2.bluetie.com/cgi-bin/emailGetAttachment.cgi?act=11&unm=willia… alt="
I have a DSL modem (providing NAT), and I am running CFP 3.5.54375.427
WindowsXP, SP3
AVG 8.0.175
I use PopPeeper to read my email. It queries online email like yahoo.com and
downloads and displays it. I don’t think PopPeeper is the problem here.
I think if I had read my mail online with FF, I would have had the same problem.
How does the webbug get through my security?
I thought that the modem NAT would have blocked this request.
When I test my ports with Shields UP, I find that port 1080 is in stealth mode
even with CFP turned off.
How can the webbug penetrate port 1080, and Shields UP cannot?
I believe that the webbug can access my IP address and maybe the PopPeeper process name.
Is it because the webbug has a process name (PopPeeper) and my IP address?
Whereas Shields UP only has my IP address?
Thanks for listening, any pointers or explanation would be appreciated
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